[JS] Subtree of Another Tree
2022. 8. 13. 13:07
🔒 문제 (LeetCode 572)
Given the roots of two binary trees root and subRoot, return true if there is a subtree of root with the same structure and node values of subRoot and false otherwise.
A subtree of a binary tree tree is a tree that consists of a node in tree and all of this node's descendants. The tree tree could also be considered as a subtree of itself.
Constraints:
- The number of nodes in the root tree is in the range [1, 2000].
- The number of nodes in the subRoot tree is in the range [1, 1000].
- -104 <= root.val <= 104
- -104 <= subRoot.val <= 104
🌊 입출력
Example 1:
Input: root = [3,4,5,1,2], subRoot = [4,1,2]
Output: true
Example 2:
Input: root = [3,4,5,1,2,null,null,null,null,0], subRoot = [4,1,2]
Output: false
🔑 해결
🌌 알고리즘 - DFS
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @param {TreeNode} subRoot
* @return {boolean}
*/
var isSubtree = function(root, subRoot) {
const areEqual = (node1, node2) => {
if(!node1 || !node2) return !node1 && !node2;
if(node1.val !== node2.val) return false;
return areEqual(node1.left, node2.left) && areEqual(node1.right, node2.right);
}
const stack = [root];
while(stack.length) {
const node = stack.pop();
if(!node) continue;
if(areEqual(node, subRoot)) return true;
stack.push(node.right, node.left);
}
return false;
};
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